MVC Model Bind

[Birgit]

Hi Nurkmez,

I'll try this one out. Then i can use it as a temporary solution.
thanx a lot!

[Daniil]

Hello,

I am afraid we can't get it working as you need, because we don't have a good way to intervene the process of deserializing of an action's parameters. Please correct me if I am wrong.

You could do it manually if needed.

Example 1

public ActionResult Submit(ProductModel ProductModel)
{
    ProductModel.ComboValue1 = JSON.Deserialize<IEnumerable<ListItem>>(this.Request["_ComboValue1_state"]).ElementAt<ListItem>(0); // The ElementAt will require a check on null if no selected item in the ComboBox
    ProductModel.ComboValue2 = JSON.Deserialize<IEnumerable<ListItem>>(this.Request["_ComboValue2_state"]);

    X.Msg.Alert("ProductModel", JSON.Serialize(ProductModel)).Show();
    return this.Direct();
}

Setting up a ComboBox's ValueHiddenName property you can change a submit key.

Example 2

Html.X().ComboBoxFor(m => m.ComboValue1).Items(Model.Data).ValueHiddenName("ComboValue1"),
Html.X().ComboBoxFor(m => m.ComboValue2).Items(Model.Data).ValueHiddenName("ComboValue2"),

public ActionResult Submit(ProductModel ProductModel)
{
    ProductModel.ComboValue1 = JSON.Deserialize<IEnumerable<ListItem>>(this.Request["ComboValue1"]).ElementAt<ListItem>(0); // The ElementAt will require a check on null if no selected item in the ComboBox
    ProductModel.ComboValue2 = JSON.Deserialize<IEnumerable<ListItem>>(this.Request["ComboValue2"]);

    X.Msg.Alert("ProductModel", JSON.Serialize(ProductModel)).Show();
    return this.Direct();
}

[nurkmez]

Hello,

I am afraid we can't get it working as you need, because we don't have a good way to intervene the process of deserializing of an action's parameters. Please correct me if I am wrong.

You could do it manually if needed.

Example 1

public ActionResult Submit(ProductModel ProductModel)
{
    ProductModel.ComboValue1 = JSON.Deserialize<IEnumerable<ListItem>>(this.Request["_ComboValue1_state"]).ElementAt<ListItem>(0); // The ElementAt will require a check on null if no selected item in the ComboBox
    ProductModel.ComboValue2 = JSON.Deserialize<IEnumerable<ListItem>>(this.Request["_ComboValue2_state"]);

    X.Msg.Alert("ProductModel", JSON.Serialize(ProductModel)).Show();
    return this.Direct();
}

Setting up a ComboBox's ValueHiddenName property you can change a submit key.

Example 2

Html.X().ComboBoxFor(m => m.ComboValue1).Items(Model.Data).ValueHiddenName("ComboValue1"),
Html.X().ComboBoxFor(m => m.ComboValue2).Items(Model.Data).ValueHiddenName("ComboValue2"),

public ActionResult Submit(ProductModel ProductModel)
{
    ProductModel.ComboValue1 = JSON.Deserialize<IEnumerable<ListItem>>(this.Request["ComboValue1"]).ElementAt<ListItem>(0); // The ElementAt will require a check on null if no selected item in the ComboBox
    ProductModel.ComboValue2 = JSON.Deserialize<IEnumerable<ListItem>>(this.Request["ComboValue2"]);

    X.Msg.Alert("ProductModel", JSON.Serialize(ProductModel)).Show();
    return this.Direct();
}

Thanks Vladimir,

I did not try your solution. It will solve the problems. Thanks...

[nurkmez]

Thanks Vladimir,

I did not try your solution. It will solve the problems. Thanks...

If Ext.Net can serialize or deserialize complex model on next version, EXT.NET will gain huge advantages over competitors. I hope that you will add your work item.

Thanks you very much..

[Daniil]

I am afraid we can't get it working as you need, because we don't have a good way to intervene the process of deserializing of an action's parameters. Please correct me if I am wrong.

My colleague, Vladimir, corrected me.

Please take a look at the following example.
http://mvc.ext.net/#/DataView_Basic/Overview/

There is the following action.

public ActionResult SubmitSelectionWithValues([ModelBinder(typeof(JsonModelBinder))]Dictionary<string, string>[] images)

A ModelBinder attribute is used to affect the deserialization process.

JsonModelBinder

public class JsonModelBinder : IModelBinder
{
    public object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext)
    {
        var vpr = bindingContext.ValueProvider.GetValue(bindingContext.ModelName);
        if (vpr == null || vpr.AttemptedValue.IsEmpty())
        {
            return null;
        }
        return JSON.Deserialize(vpr.AttemptedValue, bindingContext.ModelType);
    }
}

So, if you need custom deserialization, you should implement a binder like the JsonModelBinder one and pass it to a ModelBinder attribute.

Also it is possible to set a [ModelBinder] attributed for a class.

[ModelBinder(...)]
class ProductModel 
{
    ...
}

Another approach is associating a type and a binder in Global.asax.

Hope this helps.

[nurkmez]

[QUOTE=Daniil;105622]My colleague, Vladimir, corrected me.

Sorry Daniil

Thanks for your guide.

[Daniil]

No problem!

We will appreciate any information about your progress on this issue.