[CLOSED] TreeNode JS getUI method

[softmachine2011]

Hi,

In older versions I use this code to find UI properties of a treenode

node.ui.checked
or
node.getUI().checked

And now I'm unable to find these properties. how can I find it for use it?

[Daniil]

Hi,

A Node is just a record now, there is no encapsulated UI, it is managed by View.

The related changelog item #76.
https://examples2.ext.net/#/Getting_...nts/CHANGELOG/

76. TreeNode has been renamed to Node. Node has no client side getUI method. To get a node's HTML element, use the view's getNode method. Example //New tree.getView().getNode(node)

But in your case you should not use View, I think. There is the "checked" field in the node.

node.get("checked");

Hope this helps.

[softmachine2011]

Well, I have to use the following properties/functions:

node.ui.rendered (get) => it could be replaced by node.isVisible() ??
node.ui.toggleCheck(someVar); =>
node.ui.checkbox.checked (get) => it could be replaced by node.get('checked')

Could you correct me, and tell me what is the equivalent of toggleCheck?

[Daniil]

node.ui.rendered (get) => it could be replaced by node.isVisible() ??

I think yes.

node.ui.toggleCheck(someVar); =>

Please use:

node.set('checked', true || false);

node.ui.checkbox.checked (get) => it could be replaced by node.get('checked')

Confirm.