[CLOSED] How do I recover my original string, with accents?

[supera]

Hi

In my gridPanel, the directEvent SelectionChange call my procedure SelectionChanged, passing to the procedure the values of selected row, as follow:

<DirectEvents>
   <SelectionChange OnEvent="lstAgendasSalasSGE_SelectionChanged"
        Failure="Ext.MessageBox.alert('Load failed', 'Error during ajax event!');">
        <ExtraParams>                    
            <ext:Parameter Name="values" Value="Ext.encode(#{lstAgendasSalasSGE}.getRowsValues({selectedOnly:true}))" Mode="Raw" Encode="true" />
        </ExtraParams>
   </SelectionChange>
</DirectEvents>

the values that I get in my procedure are serialized in Json, as follow...

""[{\"IDAgendaSala\":3,\"Descricao\":\"Sala Igua\\u00e7u\",\"Detalhes\":\"\"}]""

note that the value of Description modelfield are with a code instead of ç (c cedilha, character widely used in Brazil)...
Is thus: Sala Igua\\u00e7u
and should be as follows: Sala Iguaçu

this happens with all my accented characters

I try deserialize the Json string with this code

Ext.Net.JSON.Deserialize(JsonString.Trim)

Am I doing something wrong? I´m missing some step?

Thanks for any help.

[Vladimir]

Hi,


Deserialization process doesn't decode unicode escape symbols


Try to pass deserialized string through the following function

public string DecodeUnicodeCharacters( string value ) {
        return Regex.Replace(
            value,
            @"\\u(?<Value>[a-zA-Z0-9]{4})",
            m => {
                return ((char) int.Parse( m.Groups["Value"].Value, NumberStyles.HexNumber )).ToString();
            } );
    }

[Daniil]

Hi,

Please remove one encoding:

Ext.encode()

or

Encode="true"

There is

Ext.encode(Ext.encode());

I guess it should solve the problem.

[supera]

Ok, Thanks...

Removing the tag

Encode

, worked...

I had created the role suggested by Vladimir, in VB ... follows, if it is useful to someone

    Public Shared Function DecodeUnicodeCharacteres(v As String) As String
        'tenho que percorrer a string, e onde encontrar \u, pegar os 4 próximos cararectres (que estão em hexadecimal) e converter o valor deles para toString
        Dim vPos As Integer

        vPos = InStr(1, v, "\u")
        Do While vPos <> 0
            v = v.Replace(Mid(v, vPos, 6), Chr(Integer.Parse(Mid(v, vPos + 2, 4), Globalization.NumberStyles.HexNumber)))
            vPos = InStr(1, v, "\u")
        Loop

        Return v

    End Function