[CLOSED] Simple date render question

[Jurke]

Hi
Im using this code to set the dateformat.

string strDateformat = Coolite.Utilities.DateTimeUtils.FormatNetToPHP("d");
Renderer rRenderer = new Renderer();
rRenderer.Fn = "Ext.util.Format.dateRenderer('" + strDateformat + "')";
gpViewsPerGroup.ColumnModel.Columns[3].Renderer = rRenderer;

Works great, but it does not show the time. How do I do that. I tried
string strDateformat = Coolite.Utilities.DateTimeUtils.FormatNetToPHP("d-t");
but that does not work.

HELP! :)

/mikael

[geoffrey.mcgill]

Hi Mikael,

The following Datejs documentation lists all the acceptable format specifiers, see*http://code.google.com/p/datejs/wiki/FormatSpecifiers


The .toString() function lists the .NET format specifiers, which would be passed into the .FormatNetToPHP Method.


Or, the .format() function lists the PHP format specifiers which could be passed directly into the .dateRenderer() function.


The ExtJS docs has an "official" list of accepted format specifiers, see*http://extjs.com/deploy/dev/docs/?class=Date


Hope this helps.

[Jurke]

Thanks I see. It works great.

The code now looks like this, prints out the date like the culture setting on the .NET page. then the time in 24H format ex 18:31

string strDateformat = Coolite.Utilities.DateTimeUtils.FormatNetToPHP("d");
Renderer rRenderer = new Renderer();
rRenderer.Fn = "Ext.util.Format.dateRenderer('" + strDateformat + " - H:i')";
gpViewsPerGroup.ColumnModel.Columns[3].Renderer = rRenderer;

/Mikael